मराठी

∫ 1 1 − Cos X D X - Mathematics

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प्रश्न

\[\int\frac{1}{1 - \cos x} dx\]
बेरीज
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उत्तर

\[\int\frac{dx}{1 - \cos x}\]
\[ = \int\frac{dx}{1 - \cos x} \times \frac{1 + \ cosx}{1 + \ cosx}\]
\[ = \int\left( \frac{1 + \cos x}{1 - \cos^2 x} \right)dx\]
\[ = \int\left( \frac{1 + \cos x}{\sin^2 x} \right)dx\]
\[ = \int\left( \frac{1}{\sin^2 x} + \frac{\cos x}{\sin x} \times \frac{1}{\sin x} \right)dx\]
\[ = \int\left( {cosec}^2 x + \text{cosec x }\cot x \right)dx\]
\[ = - \cot x - \text{cosec x} + C\]

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पाठ 19: Indefinite Integrals - Exercise 19.02 [पृष्ठ १५]

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आरडी शर्मा Mathematics [English] Class 12
पाठ 19 Indefinite Integrals
Exercise 19.02 | Q 29 | पृष्ठ १५

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