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प्रश्न
Which compound in the following pair will react faster in SN2 reaction with OH−?
CH3Br or CH3I
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उत्तर
In the SN2 mechanism, the reactivity of halides for the same alkyl group increases in the order. This happens because, as the size increases, the halide ion becomes a better leaving group.
R−F << R−Cl < R−Br < R−I
Therefore, CH3I will react faster than CH3Br in SN2 reactions with OH−.
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संबंधित प्रश्न
Discuss the mechanism of alkaline hydrolysis of bromomethane.
Write the major products(s) in the following:
Write the structure of the major product in each of the following reaction :
What are ambident nucleophiles? Explain with an example.
Which compound in the following pair will react faster in SN2 reaction with OH−?
(CH3)3CCl or CH3Cl
Write the structure of the major organic product in the following reaction:
\[\ce{CH3CH(Br)CH2CH3 + NaOH ->[water]}\]
Arrange the compounds of the following set in order of reactivity towards SN2 displacement:
1-Bromobutane, 1-Bromo-2, 2-dimethylpropane, 1-Bromo-2-methylbutane, 1-Bromo-3-methylbutane
What happens when ethyl chloride is treated with aqueous KOH?
Given reasons: SN1 reactions are accompanied by racemization in optically active alkyl halides.
What is the action of the following on ethyl bromide?
moist silver oxide
In the SN1 reaction, racemization takes place. It is due to:
The reaction of C6H5–CH=CH–CH3 with HBr produces:
The increasing order of reactivity towards SN1 mechanism is:
(I) \[\begin{array}{cc}
\ce{CH3-CH-CH2-CH3}\\
|\phantom{........}\\
\ce{CH3}\phantom{.....}
\end{array}\]
(II) CH3CH2CH2Cl
(III) P–CH3O–C6H4–CH2Cl
Match the reactions given in Column I with the types of reactions given in Column II.
| Column I | Column II | |
| (i) |  |
(a) Nucleophilic aromatic substitution |
| (ii) | \[\begin{array}{cc} \ce{CH3 - CH = CH2 + HBr -> CH3 - CH - CH3}\\ \phantom{............................}|\phantom{}\\ \phantom{.............................}\ce{Br}\phantom{} \end{array}\] |
(b) Electrophilic aromatic substitution |
| (iii) |  |
(c) Saytzeff elimination |
| (iv) |  |
(d) Electrophilic addition |
| (v) | \[\begin{array}{cc} \ce{CH3 CH2 CH CH3 ->[alc.KOH] CH3 CH = CH CH3}\\ \phantom{}|\phantom{..........................}\\ \phantom{}\ce{Br}\phantom{........................} \end{array}\] |
(e) Nucleophilic substitution (SN1) |
Give reason for the following:
The product formed during SN1 reaction is a racemic mixture.
The number of chiral alcohol (s) with molecular formula C4H10O is ______.
Inversion of configuration occurs in ______.
The correct order of increasing reactivity of
C-X bond towards nucleophile in the following compounds is:
