Advertisements
Advertisements
प्रश्न
CH3CO2H or CH2FCO2H
Advertisements
उत्तर
|
It is difficult for the proton to escape because the +I effect of −CH3 group increases the electron density in the O–H bond. |
The release of the proton is easy because the −I effect of −F reduces the electron density in the O–H bond. |
|
The +I effect due to the concentration of negative charge destabilises the carboxylate ion. |
The spreading of the negative charge causes the –I effect to stabilize the carboxylate ion. |
Hence, due to lower electron density in the O–H bond and higher stability of FCH2COO– ion, FCH2COOH is a stronger acid than CH3COOH.
APPEARS IN
संबंधित प्रश्न
How is 1-nitropropane prepared from suitable oxime?
How are 2 - nitropropane prepared from suitable oxime?
Although phenoxide ion has more number of resonating structures than carboxylate ion, carboxylic acid is a stronger acid than phenol. Give two reasons.
Why pKa of F-CH2-COOH is lower than that of Cl−CH2−COOH?
Distinguish between the following : Benzoic acid and methyl benzoate
Which acid of the pair shown here would you expect to be stronger?
Arrange the following compounds in increasing order of their property as indicated:
Benzoic acid, 4-Nitrobenzoic acid, 3, 4-Dinitrobenzoic acid, 4-Methoxybenzoic acid (acid strength)
Write the reactions involved Hell-Volhard Zelinsky reaction?
Complete the following reaction sequence.
\[\begin{array}{cc}
\ce{O}\phantom{...............................................}\\
||\phantom{...............................................}\\
\ce{CH3 - C - CH3 ->[(i) CH3MgBr][H2O] (A) ->[Na metal][Ether] (B) ->[CH3 - Br] (C)}
\end{array}\]
Acidity of BF3 can be explained on the basis of which of the following concepts?
A mixture of benzaldehyde and formaldehyde on heating with 50% NaOH solution gives
Na2CO3 cannot be used in place of (NH4)2CO3 for the precipitation of the V group because ______.
Formic acid and formaldehyde can be distinguished by treating with ______.
Describe the action of alcoholic potassium hydroxide (alc. KOH) on ethyl bromide
Describe the action of alcoholic potassium hydroxide (alc. KOH) on n-propyl bromide
Describe the action of alcoholic potassium hydroxide (alc. KOH) on isopropyl bromide.
An ester is boiled with KOH. The product is cooled and acidified with conc. HCL. A white crystalline acid separates. The ester is:
