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प्रश्न
CH3CO2H or CH2FCO2H
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उत्तर
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It is difficult for the proton to escape because the +I effect of −CH3 group increases the electron density in the O–H bond. |
The release of the proton is easy because the −I effect of −F reduces the electron density in the O–H bond. |
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The +I effect due to the concentration of negative charge destabilises the carboxylate ion. |
The spreading of the negative charge causes the –I effect to stabilize the carboxylate ion. |
Hence, due to lower electron density in the O–H bond and higher stability of FCH2COO– ion, FCH2COOH is a stronger acid than CH3COOH.
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संबंधित प्रश्न
Although phenoxide ion has more number of resonating structures than carboxylate ion, carboxylic acid is a stronger acid than phenol. Give two reasons.
Why pKa of F-CH2-COOH is lower than that of Cl−CH2−COOH?
Distinguish between the following : Benzoic acid and methyl benzoate
Which acid of the pair shown here would you expect to be stronger?
CH2FCH2CH2CO2H or CH3CHFCH2CO2H
Which acid of the pair shown here would you expect to be stronger?

Arrange the following compounds in increasing order of their property as indicated:
CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)
Arrange the following compounds in increasing order of their property as indicated:
Benzoic acid, 4-Nitrobenzoic acid, 3, 4-Dinitrobenzoic acid, 4-Methoxybenzoic acid (acid strength)
Account for the following:
Carboxylic acid is a stronger acid than phenol.
What happens when Salicylic acid is treated with (CH3CO)2 O/H+?
Arrange the following compounds in increasing order of their property as indicated:
F - CH2COOH, O2N - CH2 COOH CH3 COOH,HCOOH - acid character.
Assertion: Formaldehyde is a planar molecule.
Reason: It contains sp2 hybridised carbon atom.
When propionamide reacts with Br2 in the presence of alkali the product is ______.
Formic acid and formaldehyde can be distinguished by treating with ______.
Describe the action of alcoholic potassium hydroxide (alc. KOH) on ethyl bromide




