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प्रश्न
CH3CO2H or CH2FCO2H
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उत्तर
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It is difficult for the proton to escape because the +I effect of −CH3 group increases the electron density in the O–H bond. |
The release of the proton is easy because the −I effect of −F reduces the electron density in the O–H bond. |
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The +I effect due to the concentration of negative charge destabilises the carboxylate ion. |
The spreading of the negative charge causes the –I effect to stabilize the carboxylate ion. |
Hence, due to lower electron density in the O–H bond and higher stability of FCH2COO– ion, FCH2COOH is a stronger acid than CH3COOH.
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संबंधित प्रश्न
How are 2 - nitropropane prepared from suitable oxime?
Which acid of the pair shown here would you expect to be stronger?
CH2FCO2H or CH2ClCO2H
Which acid of the pair shown here would you expect to be stronger?
CH2FCH2CH2CO2H or CH3CHFCH2CO2H
Which acid of the pair shown here would you expect to be stronger?
Arrange the following compounds in increasing order of their property as indicated:
CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)
Account for the following:
Carboxylic acid is a stronger acid than phenol.
Arrange the following compounds in increasing order of their property as indicated:
F - CH2COOH, O2N - CH2 COOH CH3 COOH,HCOOH - acid character.
Complete the following reaction sequence.
\[\begin{array}{cc}
\ce{O}\phantom{...............................................}\\
||\phantom{...............................................}\\
\ce{CH3 - C - CH3 ->[(i) CH3MgBr][H2O] (A) ->[Na metal][Ether] (B) ->[CH3 - Br] (C)}
\end{array}\]
Acidity of BF3 can be explained on the basis of which of the following concepts?
Na2CO3 cannot be used in place of (NH4)2CO3 for the precipitation of the V group because ______.
Formic acid and formaldehyde can be distinguished by treating with ______.
Describe the action of alcoholic potassium hydroxide (alc. KOH) on ethyl bromide
Describe the action of alcoholic potassium hydroxide (alc. KOH) on n-propyl bromide
Describe the action of alcoholic potassium hydroxide (alc. KOH) on isopropyl bromide.
The correct order of decreasing acidity of the following aliphatic acids is:
