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प्रश्न
Write the reactions involved Hell-Volhard Zelinsky reaction?
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उत्तर
Hell-Volhard Zelinsky reaction: Carboxylic acid having α-hydrogen are halogenated at α- position on treatment with chlorine or bromine in the presence of red phosphorous to give α-halogenated carboxylic acid.
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संबंधित प्रश्न
Distinguish between the following : Benzoic acid and methyl benzoate
Which acid of the pair shown here would you expect to be stronger?
CH2FCH2CH2CO2H or CH3CHFCH2CO2H
Arrange the following compounds in increasing order of their property as indicated:
CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)
Account for the following:
Carboxylic acid is a stronger acid than phenol.
Complete the following reaction sequence.
\[\begin{array}{cc}
\ce{O}\phantom{...............................................}\\
||\phantom{...............................................}\\
\ce{CH3 - C - CH3 ->[(i) CH3MgBr][H2O] (A) ->[Na metal][Ether] (B) ->[CH3 - Br] (C)}
\end{array}\]
Assertion: Formaldehyde is a planar molecule.
Reason: It contains sp2 hybridised carbon atom.
Acidity of BF3 can be explained on the basis of which of the following concepts?
A mixture of benzaldehyde and formaldehyde on heating with 50% NaOH solution gives
Na2CO3 cannot be used in place of (NH4)2CO3 for the precipitation of the V group because ______.
Describe the action of alcoholic potassium hydroxide (alc. KOH) on isopropyl bromide.
