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प्रश्न
Write the reactions involved Hell-Volhard Zelinsky reaction?
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उत्तर
Hell-Volhard Zelinsky reaction: Carboxylic acid having α-hydrogen are halogenated at α- position on treatment with chlorine or bromine in the presence of red phosphorous to give α-halogenated carboxylic acid.
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संबंधित प्रश्न
Although phenoxide ion has more number of resonating structures than carboxylate ion, carboxylic acid is a stronger acid than phenol. Give two reasons.
Arrange the following compounds in increasing order of their property as indicated:
CH3CH2CH(Br)COOH, CH3CH(Br)CH2COOH, (CH3)2CHCOOH, CH3CH2CH2COOH (acid strength)
Account for the following:
Carboxylic acid is a stronger acid than phenol.
What happens when Salicylic acid is treated with (CH3CO)2 O/H+?
Assertion: Formaldehyde is a planar molecule.
Reason: It contains sp2 hybridised carbon atom.
Acidity of BF3 can be explained on the basis of which of the following concepts?
Formic acid and formaldehyde can be distinguished by treating with ______.
Describe the action of alcoholic potassium hydroxide (alc. KOH) on ethyl bromide
Describe the action of alcoholic potassium hydroxide (alc. KOH) on isopropyl bromide.
The correct order of decreasing acidity of the following aliphatic acids is:
