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प्रश्न
When 1 mol \[\ce{CrCl3.6H2O}\] is treated with excess of \[\ce{AgNO3}\], 3 mol of \[\ce{AgCl}\] are obtained. The formula of the complex is ______.
विकल्प
\[\ce{[CrCl3 (H2O)3].3H2O}\]
\[\ce{[CrCl2 (H2O)4]Cl.2H2O}\]
\[\ce{CrCl(H2O)5]Cl2.H2O}\]
\[\ce{[Cr(H2O)6]Cl3}\]
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उत्तर
When 1 mol \[\ce{CrCl3.6H2O}\] is treated with excess of \[\ce{AgNO3}\], 3 mol of \[\ce{AgCl}\] are obtained. The formula of the complex is \[\ce{[Cr(H2O)6]Cl3}\].
Explanation:
One mol of \[\ce{AgCl}\] is precipitated by one mole of \[\ce{Cl^-}\], therefore three moles of \[\ce{AgCl}\] would get precipitared by three moles of chloride ions, \[\ce{Cl^-}\] and in this case \[\ce{3Cl^-}\] are present in ionization sphere (i.e. out side the coordination sphere) in complex at \[\ce{[Cr(H2O)6]Cl3}\], therefore when 1 mol of it is treated with excess of this complex 3 mols of \[\ce{AgCl}\] is precipitated.
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Which of the following complexes are heteroleptic?
(i) \[\ce{[Cr(NH3)6]^{3+}}\]
(ii) \[\ce{[Fe(NH3)4]Cl2]^+}\]
(iii) \[\ce{[Mn(CN)6]^{4-}}\]
(iv) \[\ce{[Co(NH3)4]Cl2]}\]
Match the complex ions given in Column I with the colours given in Column II and assign the correct code:
| Column I (Complex ion) | Column II (Colour) |
| A. \[\ce{[Co(NH3)6]^{3+}}\] | 1. Violet |
| B. \[\ce{[Ti(H2O)6]^{3+}}\] | 2. Green |
| C. \[\ce{[Ni(H2O)6]^{2+}}\] | 3. Pale blue |
| D. \[\ce{(Ni(H2O)4 (en)]^{2+} (aq)}\] | 4. Yellowish orange |
| 5. Blue |
Match the coordination compounds given in Column I with the central metal atoms given in Column II and assign the correct code:
| Column I (Coordination Compound) | Column II (Central metal atom) |
| A. Chlorophyll | 1. rhodium |
| B. Blood pigment | 2. cobalt |
| C. Wilkinson catalyst | 3. calcium |
| D. Vitamin B12 | 4. iron |
| 5. magnesium |
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