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प्रश्न
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उत्तर
We know pressure exerted by a liquid column of height h, density p is
P = h x p x g.
The pressure exerted by the mercury column of height 76 cm.
Density of mercury = 13.6 g/cc = 1.36 x 104kg/m3.
Pmercury = 0.76 x 1.36 x 104 x 9.8 = 10.12 x 104 Nm-2.
Let the height of the water column = hm.
Density of water = 1g/cc= 103 kg/m3.
Pwater = h x 103 x 9.8 = 9.8h x103 Nm-2.
Now put Pmercury = Pwater
9.8 h x103 = 10.12 x 104
h = 10.12/9.8 = 10.34 m.
So, 10.34 m height of water column would exert the same pressure on its base as a 76 cm column of mercury.
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[Density of mercury = 13600 kg/m3 and g = 10 m/s2]
(i) Calculate the height of a water column which will exert on its base the same
Pressure as the 70 cm column of mercury.
(ii) Will the height of the water column change if the cross-section of the water column is made wider?
What fact about liquid pressure does the following diagram in the following figure illustrate?
