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प्रश्न
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उत्तर
We know pressure exerted by a liquid column of height h, density p is
P = h x p x g.
The pressure exerted by the mercury column of height 76 cm.
Density of mercury = 13.6 g/cc = 1.36 x 104kg/m3.
Pmercury = 0.76 x 1.36 x 104 x 9.8 = 10.12 x 104 Nm-2.
Let the height of the water column = hm.
Density of water = 1g/cc= 103 kg/m3.
Pwater = h x 103 x 9.8 = 9.8h x103 Nm-2.
Now put Pmercury = Pwater
9.8 h x103 = 10.12 x 104
h = 10.12/9.8 = 10.34 m.
So, 10.34 m height of water column would exert the same pressure on its base as a 76 cm column of mercury.
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संबंधित प्रश्न
What is the pressure exerted by 75 cm vertical column of mercury of density 13600 kgm−3 in SI units?
[Take g = 9.8 ms−2].
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The normal pressure of air is 76 cm of mercury. Calculate the pressure in SI units.
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(i) Calculate the height of a water column which will exert on its base the same
Pressure as the 70 cm column of mercury.
(ii) Will the height of the water column change if the cross-section of the water column is made wider?
What fact about liquid pressure does the following diagram in the following figure illustrate?

What is the SI unit of density?
What do you mean by relative density?
