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प्रश्न
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उत्तर
The force acting normally on a surface is known as thrust.
SI unit of thrust is N.
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संबंधित प्रश्न
What is the pressure exerted by 75 cm vertical column of mercury of density 13600 kgm−3 in SI units?
[Take g = 9.8 ms−2].
Pressure at the bottom of the sea at some particular place is 8968960 Pa. If the density of seawater is 1040 kgm3 calculate the depth of the sea. Take g = 9.8 ms−2. Neglect the pressure of the atmosphere.
Calculate the equivalent height of mercury, which will exert as much pressure as 960 m of seawater of density 1040 kgm−3. The density of mercury is 13600 kgm−3.
The pressure of water on the ground floor is 160000 Pa. Calculate the pressure on the fifth floor, at a height of 15 m.
The normal pressure of air is 76 cm of mercury. Calculate the pressure in SI units.
[Density of mercury = 13600 kg/m3 and g = 10 m/s2]
(i) Calculate the height of a water column which will exert on its base the same
Pressure as the 70 cm column of mercury.
(ii) Will the height of the water column change if the cross-section of the water column is made wider?
What fact about liquid pressure does the following diagram in the following figure illustrate?
What do you mean by relative density?
