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प्रश्न
Using ruler and compasses only, construct a parallelogram ABCD, in which : AB = 6 cm, AD = 3 cm and ∠DAB = 60°. In the same figure draw the bisector of angle DAB and let it meet DC at point P. Measure angle APB.
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उत्तर

Steps :
- Draw AB = 6 cm.
- At A draw ∠QAB = 60°.
- From AQ cut AD = 3 cm.
- From D, draw an arc of radius 6 cm.
- From B, draw an arc of radius 3 cm which meets the first arc at C.
- Join CD and BC.
Thus ABCD is the required ||gm. - Bisect ∠DAB, so that bisector meets CD at P.
- Join PB and measure ZAPB.
∴ ∠APB = 90°.
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संबंधित प्रश्न
The perpendicular distance between the pair of opposite sides of a parallelogram are 3 cm and 4 cm, and one of its angles measures 60o. Using a ruler and compasses only,
construct the parallelogram.
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Construct a parallelogram ABCD, when:
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Construct a parallelogram ABCD, when:
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Construct a parallelogram ABCD, if :
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Construct a parallelogram ABCD, if :
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Construct a parallelogram ABCD, if :
AB = 5.8 cm, AD = 4.6 cm and diagonal AC = 7.5 cm.
Construct a parallelogram ABCD, if :
lengths of diagonals AC and BD are 6.3 cm and 7.0 cm respectively, and the angle between them is 45°.
Construct a parallelogram ABCD, if :
lengths of diagonals AC and BD are 5.4 cm and 6.7 cm respectively and the angle between them is 60°.
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