Question

Construct a parallelogram ABCD, when:

AB = 4.5 cm, ∠B = 120° and the distance between AB and DC = 3.0 cm.

Answer 1

Steps:

1. Draw AB = 4.5 cm.
2. At B, draw BP ⊥ AB.
3. From BP cut BE = 3 cm.
4. Through E, draw a perpendicular to BP to get QR parallel to AB.
5. Draw BP, such that ∠B = 120°.
6. Let BP intersect QR at C.
7. With A as center and radius = BC, draw an arc cutting QR at D.
8. Join AD, BC and CD.

ABCD is the required parallelogram.