Advertisements
Advertisements
प्रश्न
Draw a parallelogram ABCD, with AB = 6 cm, AD = 4.8 cm and ∠DAB = 45°. Draw the perpendicular bisector of side AD and let it meet AD at point P. Also, draw the diagonals AC and BD; and let them intersect at point O. Join O and P. Measure OP.
Advertisements
उत्तर

Steps :
- Draw AB = 6 cm.
- Draw ∠PAB = 45°.
- Cut AD = 4.8 cm.
- From D, draw an arc of radius 6 cm.
- From B, draw an arc of radius 4.8 cm which meets the first arc at C.
- Join BC, CD, AD.
Thus ABCD is the required ||gm. - Draw perpendicular bisector XY of AD which cuts AD at P.
- Join AC and BD which intersect at O.
- Join OP and measure it.
OP = 3 cm.
APPEARS IN
संबंधित प्रश्न
Construct a parallelogram ABCD, when:
AB = 4.4 cm, AD = 6.2 cm and AC = 4.8 cm.
The perpendicular distance between the pair of opposite sides of a parallelogram are 3 cm and 4 cm, and one of its angles measures 60o. Using a ruler and compasses only,
construct the parallelogram.
Construct a parallelogram ABCD, when:
AB = 6.0 cm, AD = 5.0 cm and ∠A = 45°.
Construct a parallelogram ABCD, when:
Base AB = 6.5 cm, BC = 4 cm and the altitude corresponding to AB = 3.1 cm.
Construct a parallelogram ABCD, if :
AB = 3.6 cm, BC = 4.5 cm and ∠ABC = 120°.
Construct a parallelogram ABCD, if :
AD = 4 cm, DC = 5 cm and diagonal BD = 7 cm.
Construct a parallelogram ABCD, if :
diagonal AC = 6.4 cm, diagonal BD = 5.6 cm and angle between the diagonals is 75°.
Construct a parallelogram ABCD, if :
lengths of diagonals AC and BD are 6.3 cm and 7.0 cm respectively, and the angle between them is 45°.
Construct a parallelogram PQRS in which PQ = 6.4cm, QR = 4cm and the distance between PQ and SR is 3cm.
Construct a parallelogram ABCD in which AB = 4.5cm, ∠A = 105° and the distance between AB and CD is 3.2cm.
