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प्रश्न
Construct a parallelogram PQRS in which PQ = 6.4cm, QR = 4cm and the distance between PQ and SR is 3cm.
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उत्तर
Steps of Construction:
1) Draw PQ = 6.4cm.
2) At Q, draw QX perpendicular to PQ.
3) From QX, cut QT = 3cm = distance between PQ and SR.
4) Through T, draw a perpendicular to QX to get ZY parallel to PQ.
5) With P as centre and radius = QR = 4cm, draw an arc which cuts ZY at S.
6) With Q as centre and radius = 4cm, draw an arc which cuts ZY at R.
7) ABCD is the required parallelogram.
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संबंधित प्रश्न
Construct a parallelogram ABCD, when:
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Construct a parallelogram ABCD, when:
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Construct a parallelogram ABCD, when:
AB = 6.0 cm, AD = 5.0 cm and ∠A = 45°.
Construct a parallelogram ABCD, when:
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Construct a parallelogram ABCD, when:
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Construct a parallelogram ABCD, if :
BC = 4.5 cm, CD = 5.2 cm and ∠ADC = 75°.
Construct a parallelogram ABCD, if :
AB = 5.8 cm, AD = 4.6 cm and diagonal AC = 7.5 cm.
Construct a parallelogram ABCD, if :
diagonal AC = 6.4 cm, diagonal BD = 5.6 cm and angle between the diagonals is 75°.
Construct a parallelogram ABCD, if :
lengths of diagonals AC and BD are 6.3 cm and 7.0 cm respectively, and the angle between them is 45°.
Construct a parallelogram ABCD. Given:
AB = 3.5cm, AC = 4cm and BD = 5.2cm
