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प्रश्न
Construct a parallelogram PQRS in which PQ = 6.4cm, QR = 4cm and the distance between PQ and SR is 3cm.
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उत्तर
Steps of Construction:
1) Draw PQ = 6.4cm.
2) At Q, draw QX perpendicular to PQ.
3) From QX, cut QT = 3cm = distance between PQ and SR.
4) Through T, draw a perpendicular to QX to get ZY parallel to PQ.
5) With P as centre and radius = QR = 4cm, draw an arc which cuts ZY at S.
6) With Q as centre and radius = 4cm, draw an arc which cuts ZY at R.
7) ABCD is the required parallelogram.
संबंधित प्रश्न
The perpendicular distance between the pair of opposite sides of a parallelogram are 3 cm and 4 cm, and one of its angles measures 60o. Using a ruler and compasses only,
construct the parallelogram.
Construct a parallelogram ABCD, when:
AB = 5.8 cm, diagonal AC = 8.2 cm and diagonal BD = 6.2 cm.
Construct a parallelogram ABCD, when:
AB = 6.0 cm, AD = 5.0 cm and ∠A = 45°.
Construct a parallelogram ABCD, when:
Base AB = 6.5 cm, BC = 4 cm and the altitude corresponding to AB = 3.1 cm.
Construct a parallelogram ABCD, if :
AD = 4 cm, DC = 5 cm and diagonal BD = 7 cm.
Construct a parallelogram ABCD, if :
AB = 5.8 cm, AD = 4.6 cm and diagonal AC = 7.5 cm.
Construct a parallelogram ABCD, if :
diagonal AC = 6.4 cm, diagonal BD = 5.6 cm and angle between the diagonals is 75°.
Construct a parallelogram ABCD, if :
lengths of diagonals AC and BD are 6.3 cm and 7.0 cm respectively, and the angle between them is 45°.
Using ruler and compasses only, construct a parallelogram ABCD, in which : AB = 6 cm, AD = 3 cm and ∠DAB = 60°. In the same figure draw the bisector of angle DAB and let it meet DC at point P. Measure angle APB.
Construct a parallelogram ABCD. Given:
AB = 5.5cm, BC = 3.5cm, ∠B = 75°
