हिंदी

Using Ampere’s circuital law, obtain an expression for magnetic flux density ‘B’ at a point near an infinitely long and straight conductor, carrying a current I.

Advertisements
Advertisements

प्रश्न

Using Ampere’s circuital law, obtain an expression for magnetic flux density ‘B’ at a point near an infinitely long and straight conductor, carrying a current I.

संख्यात्मक
Advertisements

उत्तर

Consider a point P at a distance from a straight infinity long wire (conductor) carrying a current I in free space.

Because of the axial symmetry about the straight wire, the magnetic induction has the same magnitude B at all points on a circle in a transverse plane and centred on the wire. We therefore choose an Amperian loop, a circle of radius r centred on the wire with its plane perpendicular to the wire.

`vec"B"` is everywhere tangential to the circular Amperian loop.

Angle θ = 0° (between `vec"B" and vec"dl"`) at all points on the loop.

`oint vec"B" * vec"dl" = oint "Bdl" = "B" oint "dl" = "B"(2pi"r")`

`therefore oint vec"B" * vec"dl" = mu_0"I"`

Where `mu_0` is the permeability of free space.

B = `(mu_0 "I")/(2pi"r")`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2022-2023 (March) Official

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

Obtain an expression for magnetic induction along the axis of the toroid.


A long straight wire of a circular cross-section of radius ‘a’ carries a steady current ‘I’. The current is uniformly distributed across the cross-section. Apply Ampere’s circuital law to calculate the magnetic field at a point ‘r’ in the region for (i) r < a and (ii) r > a.


In Ampere's  \[\oint \vec{B}  \cdot d \vec{l}  =  \mu_0 i,\] the current outside the curve is not included on the right hand side. Does it mean  that the magnetic field B calculated by using Ampere's law, gives the contribution of only the currents crossing the area bounded by the curve?  


Sometimes we show an idealised magnetic field which is uniform in a given region and falls to zero abruptly. One such field is represented in figure. Using Ampere's law over the path PQRS, show that such a field is not possible. 


Find the magnetic field due to a long straight conductor using Ampere’s circuital law.


A long solenoid has a radius a and number of turns per unit length n. If it carries a current i, then the magnetic field on its axis is directly proportional to ______.

Which of the following is the correct definition of ampere?

A solenoid of length 0.6 m has a radius of 2 cm and is made up of 600 turns If it carries a current of 4 A, then the magnitude of the magnetic field inside the solenoid is:


A thick current carrying cable of radius ‘R’ carries current ‘I’ uniformly distributed across its cross-section. The variation of magnetic field B(r) due to the cable with the distance ‘r’ from the axis of the cable is represented by:


Read the following paragraph and answer the questions.

Consider the experimental set-up shown in the figure. This jumping ring experiment is an outstanding demonstration of some simple laws of Physics. A conducting non-magnetic ring is placed over the vertical core of a solenoid. When current is passed through the solenoid, the ring is thrown off.

  1. Explain the reason for the jumping of the ring when the switch is closed in the circuit.
  2. What will happen if the terminals of the battery are reversed and the switch is closed? Explain.
  3. Explain the two laws that help us understand this phenomenon.

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×