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There Are Three Copies Each of 4 Different Books. in How Many Ways Can They Be Arranged in a Shelf? - Mathematics

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प्रश्न

There are three copies each of 4 different books. In how many ways can they be arranged in a shelf?

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उत्तर

Total number of books = 12
∴ Required number of arrangements = Arrangements of 12 things of which each of the 4 different books has three copies =\[\frac{12!}{3!3!3!3!}\]=\[\frac{12!}{(3! )^4}\]

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Factorial N (N!) Permutations and Combinations
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अध्याय 16: Permutations - Exercise 16.5 [पृष्ठ ४३]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 16 Permutations
Exercise 16.5 | Q 15 | पृष्ठ ४३

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