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A Biologist Studying the Genetic Code is Interested to Know the Number of Possible Arrangements of 12 Molecules in a Chain. the Chain Contains 4 Different Molecules Represented by the Initials a - Mathematics

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प्रश्न

A biologist studying the genetic code is interested to know the number of possible arrangements of 12 molecules in a chain. The chain contains 4 different molecules represented by the initials A (for Adenine), C (for Cytosine), G (for Guanine) and T (for Thymine) and 3 molecules of each kind. How many different such arrangements are possible?

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उत्तर

Number of molecules in a chain = 12
Number of molecules with initials A = 3
Number of molecules with initials C = 3
Number of molecules with initials G = 3
Number of molecules with initials T = 3
Thus, total arrangements of all the molecules in the chain = Number of arrangements of 12 things of which 3 are similar to the first kind, 3 are similar to the second kind, 3 are similar to the third kind and 3 are similar to the fourth kind
=\[\frac{12!}{3!3!3!3!}\]= 369600

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Factorial N (N!) Permutations and Combinations
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 16: Permutations - Exercise 16.5 [पृष्ठ ४३]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 16 Permutations
Exercise 16.5 | Q 17 | पृष्ठ ४३

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