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If P (N, 5) : P (N, 3) = 2 : 1, Find N. - Mathematics

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प्रश्न

If P (n, 5) : P (n, 3) = 2 : 1, find n.

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उत्तर

We have, P (n, 5):P (n, 3) = 2:1

\[\Rightarrow \frac{n!}{\left( n - 5 \right)!} \times \frac{\left( n - 3 \right)!}{n!} = \frac{2}{1}\]
\[ \Rightarrow \frac{n!}{\left( n - 5 \right)!} \times \frac{\left( n - 3 \right)\left( n - 4 \right)\left( n - 5 \right)!}{n!} = \frac{2}{1}\]
\[ \Rightarrow \left( n - 3 \right)\left( n - 4 \right) = 2\]
\[ \Rightarrow \left( n - 3 \right)\left( n - 4 \right) = 2 \times 1\]
\[\text{Thus, on comparing the LHS and the RHS in above expression, we get}, \]
\[n - 3 = 2\]
\[ \Rightarrow n = 5 \]

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Factorial N (N!) Permutations and Combinations
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अध्याय 16: Permutations - Exercise 16.3 [पृष्ठ २८]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 16 Permutations
Exercise 16.3 | Q 11 | पृष्ठ २८

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