Advertisements
Advertisements
प्रश्न
The voltage across a 3Ω resistance is 6 V. How large is the current? What is
the resistance of a filament lamp when a voltage of 3 V across it causes a
current of 0.5 A?
Advertisements
उत्तर
If voltage, V = 6 volt and resistance R = 3Ω
The a/c to ohm's law, current I = `"V"/"R" = 6/3 = 2 "A"`
For filament lamp:
Given that, voltage= 3 V, current= 0.5 A.
let R be the resistance of the filament lamp;
then R = `"V"/"I" = 3/0.5` = 6Ω
APPEARS IN
संबंधित प्रश्न
A battery of emf 12 V and internal resistance 2 Ω is connected with two resistors A and B of resistance 4 Ω and 6 Ω respectively joined in series.

Find:
1) Current in the circuit
2) The terminal voltage of the cell
3) The potential difference across 6Ω Resistor
4) Electrical energy spent per minute in the 4Ω resistor.
State the relation between potential difference, work done and charge moved.
A resistance of 20 ohms has a current of 2 amperes flowing in it. What potential difference is there between its ends?
What is Ohm's law? Explain how it is used to define the unit of resistance.
In the circuit shown below:
The potential difference across the 3 Ω resistor is:
If the potential difference between the end of a wire of fixed resistance is doubled, by how much does the electric power increase?
If P and V are the power and potential of device, the power consumed with a supply potential V1 is:
What is the measure of the work done on the unit positive charge to bring it to that point against all electrical forces?
Study the following circuit and find:

- Effective resistance of the circuit
- Current drawn from the battery
- Potential difference across the 5 omega resistor
