हिंदी

The sides of an equilateral triangle are increasing at the rate of 2 cm/sec. The rate at which the area increases, when side is 10 cm is ______.

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प्रश्न

The sides of an equilateral triangle are increasing at the rate of 2 cm/sec. The rate at which the area increases, when side is 10 cm is ______.

विकल्प

  • `10 "cm"^(2/"s")`

  • `sqrt(3) "cm"^(2/"s")`

  • `10sqrt(3) "cm"^(2/"s")`

  • `10/3 "cm"^(2/"s")`

MCQ
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उत्तर

The sides of an equilateral triangle are increasing at the rate of 2 cm/sec. The rate at which the area increases, when side is 10 cm is `10sqrt(3) "cm"^2/"s"`.

Explanation:

Let the length of each side of the given equilateral triangle be x cm.

∴ `"dx"/"dt" = 2 "cm"/sec`

Area of equilateral triangle A = `sqrt(3)/4 x^2`

∴ `"dA"/"dt" = sqrt(3)/4 * 2x * "dx"/"dt"`

= `sqrt(3)/2 xx 10 xx 2`

= `10sqrt(3) "cm"^2/sec`

Hence, the rate of increasing of area = `10sqrt(3) "cm"^2/sec`.

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अध्याय 6: Application Of Derivatives - Exercise [पृष्ठ १३८]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 6 Application Of Derivatives
Exercise | Q 35 | पृष्ठ १३८

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