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The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10−11 m. What are the radii of the n = 2 and n = 3 orbits? - Physics

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प्रश्न

The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10−11 m. What are the radii of the n = 2 and n = 3 orbits?

संख्यात्मक
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उत्तर

The radius of the innermost orbit of a hydrogen atom, r1 = 5.3 × 10−11 m

Let r2 be the radius of the orbit at n = 2. It is related to the radius of the innermost orbit as:

r2 = (n)2r1

= (2)2 × 5.3 × 10−11

= 4 × 5.3 × 10−11

= 2.12 × 10−10 m

For n = 3, we can write the corresponding electron radius as:

r3 = (n)2r1

= (3)2 × 5.3 × 10−11

= 9 × 5.3 × 10−11

= 4.77 × 10−10 m

Hence, the radii of an electron for n = 2 and n = 3 orbits are 2.12 × 10−10 m and 4.77 × 10−10 m, respectively.

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अध्याय 12: Atoms - EXERCISES [पृष्ठ ३०५]

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एनसीईआरटी Physics Part 1 and 2 [English] Class 12
अध्याय 12 Atoms
EXERCISES | Q 12.7 | पृष्ठ ३०५

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