हिंदी

The wavelength of the second line of the Balmer series in the hydrogen spectrum is 4861 Å. Calculate the wavelength of the first line of the same series.

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प्रश्न

The wavelength of the second line of the Balmer series in the hydrogen spectrum is 4861 Å. Calculate the wavelength of the first line of the same series.

संख्यात्मक
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उत्तर

For the first line in Balmer series:

`1/lambda = R(1/2^2 - 1/3^2) = (5R)/36` ..........(i)

For second Balmer line:

`1/4861 = R(1/2^2 - 1/4^2) = (3R)/16` ............(ii)

Dividing equation (ii) by (i),

`lambda/4861 = (3R)/16 xx 36/(5R)`

`lambda = 4861 xx 27/20 = 6562` Å

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2022-2023 (March) Delhi Set 2

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