Advertisements
Advertisements
प्रश्न
The perpendicular distance between the point of application of force and turning point is 1.75 m when a force of 80 N acts on a rigid body. Calculate the moment of force.
Advertisements
उत्तर
Force (F) = 80 N
Perpendicular distance = 1.75 m
∴ Moment of force = F × perpendicular distance
= 80 × 1.75 = 140 Nm.
APPEARS IN
संबंधित प्रश्न
Name the factors affecting the turning effect of a body
The S.I. unit of force is kgf. (kilogram-force)
The steering wheel of a vehicle is of large diameter.
State one way to reduce the moment of given force about a given axis of rotation.
It is easier to turn the steering wheel of a large diameter than that of a small diameter. Given reason.
Two forces each of magnitude 10 N act vertically upwards and downwards respectively at the two ends A and B of a uniform rod of length 4 m which is pivoted at its midpoint O as shown in the figure. Determine the magnitude of the resultant moment of forces about the pivot O.
A uniform metre rule of weight 10gf is pivoted at its 0 mark.
What moment of force depresses the rule?
Give an example of the following uses of a machine:
to change the direction of force
State when the moment of force is positive and when it is negative.
The diagram in Fig shows two forces F1 = 5 N and F2 = 3 N acting at points A and B respectively of a rod pivoted at a point O, such that OA = 2 m and OB = 4 m.
Calculate:
- the moment of force F1 about O.
- the moment of force F2 about O.
- total moment of the two forces about O.
