Advertisements
Advertisements
प्रश्न
The perpendicular distance between the point of application of force and turning point is 1.75 m when a force of 80 N acts on a rigid body. Calculate the moment of force.
Advertisements
उत्तर
Force (F) = 80 N
Perpendicular distance = 1.75 m
∴ Moment of force = F × perpendicular distance
= 80 × 1.75 = 140 Nm.
APPEARS IN
संबंधित प्रश्न
Less force is needed when applied at a farther distance from the pivoted point.
SI. unit of moment of force is
The steering wheel of a vehicle is of large diameter.
The spanner (or wrench) has a long handle.
State the relationship between force, mass and acceleration. Draw graphs showing the relationship between Acceleration and mass for a constant force.
Name and define the S.I. and C.G.S. units of force. How are they related?
The diagram shows two forces F1 = 5 N and F2 = 3N acting at point A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m
Calculate:
- Moment of force F1 about O
- Moment of force F2 about O
- Total moment of the two forces about O.
Classify the following amongst contact and non-contact forces.
electrostatic force
Fig. 5 shows a uniform meter scale weighing 200 gf. Provided at its centre. Two weights 300 gf and 500 gf are suspended from the ruler as shown in the diagram. Calculate the resultant torque of the ruler and hence calculate the distance from mid-point where a 100 gf should be suspended to balance the meter scale.
State two factors on which moment of the force about a point depends.
