Advertisements
Advertisements
प्रश्न
The perpendicular distance between the point of application of force and turning point is 1.75 m when a force of 80 N acts on a rigid body. Calculate the moment of force.
Advertisements
उत्तर
Force (F) = 80 N
Perpendicular distance = 1.75 m
∴ Moment of force = F × perpendicular distance
= 80 × 1.75 = 140 Nm.
संबंधित प्रश्न
A force is applied on (i) a non-rigid body and (ii) a rigid body. How does the effect of the force differ in the above two cases?
A half metre rod is pivoted at the centre with two weights of 20gf and 12gf suspended at a perpendicular distance of 6 cm and 10 cm from the pivot respectively as shown below.

1) Which of the two forces acting on the rigid rod causes clockwise moment?
2) Is the rod in equilibrium?
3) The direction of 20 kgf force is reversed. What is the magnitude of the resultant moment of the forces on the rod?
In a door, handle is provided ......... from the hinges.
State the effect of force F in of the following diagram.

In Fig. a force F is applied in a direction passing through the pivoted point O of the body. Will the body rotate? Give reason to support your answer.

It is easier to open the door by pushing it at its free end.
A spanner of length 10 cm is used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.
State Newton's Second law of motion. Under what conditon does it take the form F = ma?
It is easier to turn the steering wheel of a large diameter than that of a small diameter. Given reason.
What is the work done when no net force is applied on the body?
