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The Intensity of Sound from a Point Source is 1.0 × 10−8 W M−2 at a Distance of 5.0 M from the Source.

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प्रश्न

The intensity of sound from a point source is 1.0 × 10−8 W m−2 at a distance of 5.0 m from the source. What will be the intensity at a distance of 25 m from the source?

योग
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उत्तर

Given:
The intensity I1 is 1.0 × 10−8 Wm−2,
when the distance of the point source \[r_1\]is 5 m.
Let I2 be the intensity of the point source at a distance \[r_2\]= 25 m.
As we know,

\[I   \propto \left( \frac{1}{r^2} \right) . \] 

\[\text { So }, \] 

\[\frac{I_1}{I_2} = \frac{{r_2}^2}{{r_1}^1}\] 

\[ \Rightarrow    I_2  = \frac{I_1 {r_1}^2}{{r_2}^2}\]

On substituting the respective values, we get:

\[   I_2  = \frac{1 . 0 \times {10}^{- 8} \times 25}{625}\] \[               = 4 . 0 \times  {10}^{- 10} \text { W/ m }^2\]

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अध्याय 16: Sound Waves - Exercise [पृष्ठ ३५३]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 16 Sound Waves
Exercise | Q 18 | पृष्ठ ३५३

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