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If the Intensity of Sound is Doubled, by How Many Decibels Does the Sound Level Increase?

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प्रश्न

If the intensity of sound is doubled, by how many decibels does the sound level increase?

योग
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उत्तर

Let the intensity of the sound be I and \[\beta_1\] be the sound level. If the intensity of the sound is doubled, then its sound level becomes 2I.
Sound level \[\beta_1\] is given by ,\[\beta_1  = 10   \log_{10} \frac{I}{I_0}\],

where I0 is the constant reference intensity.
When the intensity doubles, the sound level is given by:

\[\beta_2  = 10   \log_{10} \frac{2I}{I_0}\].

According to the question,

\[   \beta_2  -  \beta_1  = 10  \log\left( \frac{2I}{I} \right)\] 

\[                             = 10 \times 0 . 3010 = 3 \text{ dB }\]

The sound level is increased by 3 dB.

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अध्याय 16: Sound Waves - Exercise [पृष्ठ ३५३]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 16 Sound Waves
Exercise | Q 20 | पृष्ठ ३५३

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