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प्रश्न
The equation of the circle in the first quadrant touching each coordinate axis at a distance of one unit from the origin is ______.
विकल्प
x2 + y2 – 2x – 2y + 1 = 0
x2 + y2 – 2x – 2y – 1 = 0
x2 + y2 – 2x – 2y = 0
x2 + y2 – 2x + 2y – 1 = 0
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उत्तर
The equation of the circle in the first quadrant touching each coordinate axis at a distance of one unit from the origin is x2 + y2 – 2x – 2y + 1 = 0.
Explanation:
Since the equation can be written as (x – 1)2 + (y – 1)2 = 1
Which represents a circle touching both the axes with its centre (1, 1) and radius one unit.
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