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प्रश्न
The vertex of the parabola (y − 2)2 = 16 (x − 1) is
विकल्प
(1, 2)
(−1, 2)
(1, −2)
(2, 1)
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उत्तर
(1, 2)
Given:
(y − 2)2 = 16 (x − 1)
Let \[X = x - 1, Y = y - 2\]
∴ \[Y^2 = 16X\]
Vertex = \[\left( X = 0, Y = 0 \right) = \left( x - 1 = 0, y - 2 = 0 \right) = \left( x = 1, y = 2 \right)\]
Hence, the vertex is at (1, 2).
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