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The Dielectric Strength of Air is 3.0 × 106 V/M. a Parallel-plate Air-capacitor Has Area 20 Cm2 and Plate Separation 0.10 Mm. Find the Maximum Rms Voltage of an Ac Source

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प्रश्न

The dielectric strength of air is 3.0 × 106 V/m. A parallel-plate air-capacitor has area 20 cm2 and plate separation 0.10 mm. Find the maximum rms voltage of an AC source that can be safely connected to this capacitor.

योग
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उत्तर

Given:
Area of parallel-plate air-capacitor, A = 20 cm2
Separation between the plates, d = 0.1 mm
Dielectric strength of air, E= 3 × 106 V/m
E = `V/d`,
where V = potential difference across the capacitor
`therefore V = Ed`
`= 3xx10^6xx0.1xx10^-3`
`= 3xx10^2=300 V`
Thus, peak value of voltage is 300 V.
Maximum rms value of voltage `(V_{rms})` is given by,
`V_{rms} = V_0 /sqrt2`
= `300/sqrt2 = 212 V`

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अध्याय 39: Alternating Current - Exercises [पृष्ठ ३३०]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 39 Alternating Current
Exercises | Q 6 | पृष्ठ ३३०

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