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The decomposition of hydrocarbon follows the equation k = (4.5×1011⁢𝑠−1)⁢𝑒−28000⁢𝐾/𝑇 Calculate Ea. - Chemistry

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प्रश्न

The decomposition of hydrocarbon follows the equation k = `(4.5 xx 10^11 s^-1) e^(-28000 K//T)`

Calculate Ea.

संख्यात्मक
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उत्तर

According to the Arrhenius equation, k = `"Ae"^((-"E"_"a")/("RT"))`

∴ `-E_a/(RT) = -(28000 K)/T`

E = 28000 K × R

= 28000 K × 8.314 JK−1 mol1

= 232.79 kJ mol−1

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अध्याय 3: Chemical Kinetics - Exercises [पृष्ठ ८७]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 3 Chemical Kinetics
Exercises | Q 3.26 | पृष्ठ ८७
नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
अध्याय 4 Chemical Kinetics
'NCERT TEXT-BOOK' Exercises | Q 4.26 | पृष्ठ २८२

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