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प्रश्न
The correct structural formula of butanoic acid is
विकल्प
\[\begin{array}{cc}\phantom{..}\text{H} \phantom{...}\text{H}\phantom{....}\text{H}\phantom{..}\text{O}\phantom{..}\\
\phantom{...}|\phantom{....}|\phantom{....}|\phantom{...}||\phantom{...}\\
\text{H} - \text{C} - \text{C} = \text{C} - \text{C} - \text{H}\\
|\phantom{.............}\\
\text{H}\phantom{.............}
\end{array}\]\[\begin{array}{cc}
\text{H}\phantom{.....}\text{H}\phantom{.....}\text{H}\phantom{....}\text{O}\\
|\phantom{....}|\phantom{....}|\phantom{....}||\\
\text{H} - \text{C} - \text{C} - \text{C} - \text{C} - \text{C} - \text{OH}\\
|\phantom{....}|\phantom{....}|\phantom{..........}\\
\phantom{....}\text{H} \phantom{...}\text{H}\phantom{...}\text{H}\phantom{...}
\end{array}\]\[\begin{array}{cc}
\phantom{...}\text{H}\phantom{...}\text{H}\phantom{...}\text{H}\phantom{...}\text{H}\phantom{....}\\
\phantom{...}|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}\\
\text{H} - \text{C} - \text{C} - \text{C} - \text{C} - \text{OH}\\
\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}|\phantom{....}\\
\phantom{....}\text{H}\phantom{....} \text{H}\phantom{....}\text{H} \phantom{....}\text{H}\phantom{....}
\end{array}\]\[\begin{array}{cc}
\phantom{....}\text{H}\phantom{....}\text{H}\phantom{....}\text{H}\phantom{...}\text{O}\phantom{...}\\
\phantom{......}|\phantom{....}|\phantom{....}|\phantom{....}||\phantom{......}\\
\text{H} - \text{C} - \text{C} - \text{C} - \text{C} - \text{OH}\\
\phantom{........}|\phantom{....}|\phantom{....}|\phantom{..............}\\
\phantom{........}\text{H} \phantom{...}\text{H}\phantom{...}\text{H}\phantom{.............}
\end{array}\]
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उत्तर
\[\begin{array}{cc}
\phantom{....}\text{H}\phantom{....}\text{H}\phantom{....}\text{H}\phantom{...}\text{O}\phantom{...}\\
\phantom{......}|\phantom{....}|\phantom{....}|\phantom{....}||\phantom{......}\\
\text{H} - \text{C} - \text{C} - \text{C} - \text{C} - \text{OH}\\
\phantom{........}|\phantom{....}|\phantom{....}|\phantom{..............}\\
\phantom{........}\text{H} \phantom{...}\text{H}\phantom{...}\text{H}\phantom{.............}
\end{array}\]
Formula of butanoic acid is C3H7COOH.
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संबंधित प्रश्न
Fill in the following blank with suitable word:
The form of carbon which is known as black lead is ...........
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Name one covalent compound containing chlorine.
Draw the electron-dot structure of a hydrogen chloride molecule.
What type of bonding would you expect between Hydrogen and Chlorine?
The organic compound prepared by Wohler from an inorganic compound called ammonium cyanate was:
(a) glucose
(b) urea
(c) uric acid
(d) vinegar
Which of the following cannot exhibit isomerism?
(a) C4H10
(b) C5H12
(c) C3H8
(d) C6H14
The number of carbon atoms joined in a spherical molecule of buckminsterfullerene is:
(a) fifty
(b) sixty
(c) seventy
(d) ninety
State the type of bonding in the following molecule.
Methane
Complete the following:
When the nuclei of two different reacting atoms are of ______ mass, then a bond so formed is called ______ covalent bond. (equal, unequal, polar, non-polar)
Draw an electron dot structure of the following molecule. (Without showing the circle) :
Methane
Draw all possible structural formulae of compound from their molecular formula given below.
C3H8
Observe the straight chain hydrocarbons given below and answer the following
questions :
i) Which of the straight chain compounds from A and B is saturated and unsaturated straight chains?
ii) Name these straight chains.
iii) Write their chemical formulae and number of – CH2 - units.
The carbon compound is used in daily life is ______.
Electrons are getting added to an element Y:
Is Y getting oxidised or reduced?
State the type of bond formed, and draw Lewis structure of water.
Complete the following activity.
Write the names of the hydrocarbons for the following structural formula.
(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)
 |
Which of the following is the formula of Butanoic acid?
`"CH"_3 - "CH"_2 - "OH" overset("Alkaline""KMnO"_4 + "Heat")(->) "CH"_3 - "COOH"`
In the above given reaction, alkaline KMnO4 acts as
State the reasons, why carbon cannot
- Lose four electrons to form C4+ cation and
- Gain four electrons to form C4- anion.
How does carbon overcome this problem to form compounds?
