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प्रश्न
Complete the following:
When the nuclei of two different reacting atoms are of ______ mass, then a bond so formed is called ______ covalent bond. (equal, unequal, polar, non-polar)
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उत्तर
When the nuclei of two different reacting atoms are of unequal mass, then a bond so formed is called polar covalent band.
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संबंधित प्रश्न
Elements forming ionic compounds attain noble gas configuration by either gaining or losing electrons from their outermost shells. Give reason to explain why carbon cannot attain noble gas configuration in this manner to form its compounds.
What would be the electron dot structure of carbon dioxide which has the formula CO2?
Choose the correct answer from the options given below:
Which of the following is a common characteristic of a covalent compound?
1) high melting point
2) consists of molecules
3) always soluble in water
4) Conducts electricity when it is in the molten state
Which inert gas electron configuration do the Cl atoms in Cl2 molecule resemble? What is this electron configuration?
In forming N2 molecule, ______ electrons are shared by each atom of nitrogen.
Which inert gas does the Cl atom in HCl resemble in electron arrangement?
Explain the bonding in methane molecule using electron dot structure.
Number of valence electrons in a carbon atom is _______.
Which of the following are correct structural isomers of butane?
- \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}|\phantom{.....}|\\
\ce{H}\ce{H-C-H}\ce{H}\\
|\\
\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}\backslash\phantom{..}|\\
\phantom{....}\ce{H}\phantom{......}\ce{C - H}\phantom{}\\
\phantom{.......}|\\
\phantom{.......}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\\
\end{array}\]
Carbon can neither form C4- cation nor C4 anion. Why?
