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Solve the Given Inequality Graphically in Two-dimensional Plane: 3x + 4y ≤ 12 - Mathematics

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प्रश्न

Solve the given inequality graphically in two-dimensional plane: 3x + 4y ≤ 12

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उत्तर

3x + 4y ≤ 12

The graphical representation of 3x + 4y = 12 is given in the figure below.

This line divides the xy-plane in two half planes, I and II.

Select a point (not on the line), which lies in one of the half planes, to determine whether the point satisfies the given inequality or not.

We select the point as (0, 0).

It is observed that,

3(0) + 4(0) ≤ 12 or 0 ≤ 12, which is true

Therefore, half plane II is not the solution region of the given inequality. Also, it is evident that any point on the line satisfies the given inequality.

Thus, the solution region of the given inequality is the shaded half plane I including the points on the line.

This can be represented as follows.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Linear Inequalities - Exercise 6.2 [पृष्ठ १२७]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 11
अध्याय 6 Linear Inequalities
Exercise 6.2 | Q 3 | पृष्ठ १२७

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