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How many litres of water will have to be added to 1125 litres of the 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content?

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प्रश्न

How many litres of water will have to be added to 1125 litres of the 45% solution of acid so that the resulting mixture will contain more than 25% but less than 30% acid content?

योग
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उत्तर

Let x litres of water is required to be added.

Then, total mixture = (x + 1125) litres

It is evident that the amount of acid contained in the resulting mixture is 45% of 1125 litres.

This resulting mixture will contain more than 25% but less than 30% acid content.

∴ 30% of (1125 + x) > 45% of 1125

And, 25% of (1125 + x) < 45% of 1125

30% of (1125 + x) > 45% of 1125

⇒ `30/100 (1125 + x) > 45/100 xx 1125`

⇒ 30 (1125 + x) > 45 x 1125

⇒ 30 x 1125 + 30 x > 45 x 1125

⇒ 30x > 45 x 1125 - 30 x 1125

⇒ 30 x > (45 -30) x 1125

⇒ `x > (15 xx 1125)/30 = 562.5`

25% of (1125 + x) < 45% of 1125

⇒ 251001125 + x < 45100 × 1125

⇒ 251125 + x < 45 × 1125

⇒ 25 × 1125 + 25x < 45 × 1125

⇒ 25x < 45 × 1125 -25 × 1125

⇒ 25x < 22500

⇒ x < 900

∴ 562.5 < x < 900

Thus, the required number of litres of water that is to be added will have to be more than 562.5 but less than 900.

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अध्याय 5: Linear Inequalities - Miscellaneous Exercise [पृष्ठ ९९]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 5 Linear Inequalities
Miscellaneous Exercise | Q 13. | पृष्ठ ९९

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