Question

Six taps can fill an empty cistern in 8 hours. How much more time will be taken, if two taps go out of order? Assume, all the taps supply water at the same rate.

Answer 1

Total no. of taps = 6

Out of order taps = 2

Taps in working condition = 6  –  2 = 4

6 taps can fill an empty cistern in = 8 hours

1 tap can fill an empty cistern in = 6 x 8 hours

4 taps can fill an empty cistern in = `48/4` = 12 hours

More time taken when 2 taps are out of order = 12 – 8 = 4 hour