Advertisements
Advertisements
प्रश्न
Six taps can fill an empty cistern in 8 hours. How much more time will be taken, if two taps go out of order? Assume, all the taps supply water at the same rate.
Advertisements
उत्तर
Total no. of taps = 6
Out of order taps = 2
Taps in working condition = 6 – 2 = 4
6 taps can fill an empty cistern in = 8 hours
1 tap can fill an empty cistern in = 6 x 8 hours
4 taps can fill an empty cistern in = `48/4` = 12 hours
More time taken when 2 taps are out of order = 12 – 8 = 4 hour
APPEARS IN
संबंधित प्रश्न
50 labourers can dig a pond in 16 days. How many labourers will be required to dig another pond, double in size in 20 days?
A family of 5 persons can be maintained for 20 days with Rs.2,480. Find, how long Rs.6944 maintains a family of 8 persons?
Ten men, working for 6 days of 10 hours each, finish `5/21` of a piece of work. How many men working at the same rate and for the same number of hours each day, will be required to complete the remaining work in 8 days?
The cost of 35 envelops is ₹ 105. How many envelops can be bought for ₹ 90?
If the cost of a dozen identical articles is ₹ 672, what will be the cost of 18 such articles?
If it has rained 276 cm in the last 3 days, how many cm of rain will fall in one week (7 days)?
Assume that the rain continues to fall at the same rate.
Cost of 10 kg of wheat is ₹ 180. What is the cost of 18 kg of wheat?
A loaded truck travels 18 km in 25 minutes. If the speed remains the same, how far can it travel in 5 hours?
The temperature dropped 18 degree Celsius in the last 24 days. If the rate of temperature drop remains the same, how many degrees will the temperature drop in the next 18 days?
What is the primary objective of the "Unitary Method"?
