Advertisements
Advertisements
प्रश्न
Simplify:
(25 ÷ 28) × 2–7
Advertisements
उत्तर
Using laws of exponents,
am ÷ an = (a)m – n and am × an = (a)m + n ...[∵ a is non-zero integer]
∴ (25 ÷ 28) × (2)–7 = (2)5 – 8 × (2)–7
= (2)–3 × (2)–7
= (2)–3 – 7
= (2)–10
= `1/2^10` ...`[∵ a^-m = 1/a^m]`
= `1/1024`
APPEARS IN
संबंधित प्रश्न
3–2 can be written as ______.
The value of `(-2/3)^4` is equal to ______.
If x be any non-zero integer, then x–1 is equal to ______.
Cube of `-1/2` is ______.
Find the value of x so that `(5/3)^-2 xx (5/3)^-14 = (5/3)^(8x)`
The cells of a bacteria double in every 30 minutes. A scientist begins with a single cell. How many cells will be there after 12 hours?
Use the properties of exponents to verify that statement is true.
25(5n – 2) = 5n
In a repeater machine with 0 as an exponent, the base machine is applied 0 times. What do these machines do to a piece of chalk?
What happens when 1 cm worms are sent through these hook-ups?
For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.
