Advertisements
Advertisements
प्रश्न
Find the value [4–1 + 3–1 + 6–2]–1 = ______.
Advertisements
उत्तर
Find the value [4–1 + 3–1 + 6–2]–1 = `underlinebb(18/11)`.
Explanation:
Using law of exponents,
`a^-m = 1/a^m` ...[∵ a is non-zero integer]
∴ `[4^-1 + 3^-1 + 6^-2]^-1 = (1/4 + 1/3 + 1/36)^-1`
= `((9 + 12 + 1)/36)^-1` ...[∵ LCM of 4, 3 and 36 = 36]
= `(22/36)^-1`
= `36/22`
= `18/11`
Hence, [4–1 + 3–1 + 6–2]–1 = `18/11`
APPEARS IN
संबंधित प्रश्न
If y be any non-zero integer, then y0 is equal to ______.
If x be any non-zero integer, then x–1 is equal to ______.
For a non-zero integer x, (x4)–3 is equal to ______.
The value of `(1/2^3)^2` is equal to ______.
The expontential form for `(-2)^4 xx (5/2)^4` is 54.
Solve the following:
100–10
Find the value of n.
`(2^n xx 2^6)/2^-3 = 2^18`
If `(5^m xx 5^3 xx 5^-2)/5^-5 = 5^12`, find m.
Find a repeater machine that will do the same work as a `(xx 1/8)` machine.
Simplify:
`[(1/2)^2 - (1/4)^3]^-1 xx 2^-3`
