Advertisements
Advertisements
प्रश्न
Find the value [4–1 + 3–1 + 6–2]–1 = ______.
Advertisements
उत्तर
Find the value [4–1 + 3–1 + 6–2]–1 = `underlinebb(18/11)`.
Explanation:
Using law of exponents,
`a^-m = 1/a^m` ...[∵ a is non-zero integer]
∴ `[4^-1 + 3^-1 + 6^-2]^-1 = (1/4 + 1/3 + 1/36)^-1`
= `((9 + 12 + 1)/36)^-1` ...[∵ LCM of 4, 3 and 36 = 36]
= `(22/36)^-1`
= `36/22`
= `18/11`
Hence, [4–1 + 3–1 + 6–2]–1 = `18/11`
APPEARS IN
संबंधित प्रश्न
The reciprocal of `(2/5)^-1` is ______.
If y be any non-zero integer, then y0 is equal to ______.
Find x so that `(2/9)^3 xx (2/9)^-6 = (2/9)^(2x - 1)`
`(125 xx x^-3)/(5^-3 xx 25 xx x^-6)`
In a repeater machine with 0 as an exponent, the base machine is applied 0 times. What do these machines do to a piece of chalk?
For hook-up, determine whether there is a single repeater machine that will do the same work. If so, describe or draw it.
By what number should (–15)–1 be divided so that the quotient may be equal to (–5)–1?
If a = – 1, b = 2, then find the value of the following:
ab × ba
Simplify:
`(1/5)^45 xx (1/5)^-60 - (1/5)^(+28) xx (1/5)^-43`
