Advertisements
Advertisements
प्रश्न
Simplify:
(25 ÷ 28) × 2–7
Advertisements
उत्तर
Using laws of exponents,
am ÷ an = (a)m – n and am × an = (a)m + n ...[∵ a is non-zero integer]
∴ (25 ÷ 28) × (2)–7 = (2)5 – 8 × (2)–7
= (2)–3 × (2)–7
= (2)–3 – 7
= (2)–10
= `1/2^10` ...`[∵ a^-m = 1/a^m]`
= `1/1024`
APPEARS IN
संबंधित प्रश्न
If x be any integer different from zero and m, n be any integers, then (xm)n is equal to ______.
Which of the following is equal to `(- 3/4)^-3`?
`10^-2 = 1/100`
(–2)0 = 2
`(-8/2)^0 = 0`
Find the multiplicative inverse of (–7)–2 ÷ (90)–1.
Use the properties of exponents to verify that statement is true.
`1/4 (2^n) = 2^(n - 2)`
Find a single machine that will do the same job as the given hook-up.
a (× 599) machine followed by a (5–100) machine.
By what number should (–8)–3 be multiplied so that the product may be equal to (–6)–3?
Find x.
`(2/5)^(2x + 6) xx (2/5)^3 = (2/5)^(x + 2)`
