Advertisements
Advertisements
प्रश्न
Simplify:
`(49 xx z^-3)/(7^-3 xx 10 xx z^-5) (z ≠ 0)`
Advertisements
उत्तर
`(49 xx z^-3)/(7^-3 xx 10 xx z^-5) = ((7)^2 xx z^-3)/(7^-3 xx 10 xx z^-5)`
= `((7)^(2 + 3) xx z^(-3 + 5))/10` ...[∵ am ÷ an = (a)m – n]
= `((7)^5 z^2)/10`
= `7^5/10 z^2`
APPEARS IN
संबंधित प्रश्न
Simplify :
(– 4)5 × (– 4)-10
(–9)3 ÷ (–9)8 is equal to ______.
The value of `(1/2^3)^2` is equal to ______.
Find the value of x so that (–2)3 × (–2)–6 = (–2)2x – 1
`(125 xx x^-3)/(5^-3 xx 25 xx x^-6)`
A new born bear weighs 4 kg. How many kilograms might a five year old bear weigh if its weight increases by the power of 2 in 5 years?
The cells of a bacteria double in every 30 minutes. A scientist begins with a single cell. How many cells will be there after 24 hours?
If possible, find a hook-up of prime base number machine that will do the same work as the given stretching machine. Do not use (× 1) machines.

If possible, find a hook-up of prime base number machine that will do the same work as the given stretching machine. Do not use (× 1) machines.

The diameter of the Sun is 1.4 × 109 m and the diameter of the Earth is 1.2756 × 107 m. Compare their diameters by division.
