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Show that the magnetic field B at a point in between the plates of a parallel-plate capacitor during charging is εε0μr2dEdt (symbols having usual meaning).

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प्रश्न

Show that the magnetic field B at a point in between the plates of a parallel-plate capacitor during charging is `(ε_0mu_r)/2 (dE)/(dt)` (symbols having usual meaning).

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उत्तर

Let us assume Id be the displacement current in the region between two plates of parallel plate capacitor, in the figure.


The magnetic field at a point between two plates of capacitor  at a perpendicular distance r from the axis of plates is given by

B = `(mu_0 2I_d)/(4pir) = mu_0/(2pir) I_d = mu_0/(2pir) xx ε_r (dphi_E)/(dt)`  ......`[because I_d = (E_0dphi_E)/(dt)]`

⇒ B = `(mu_0ε_r)/(2pir) d/(dt) (Epir^2) = (mu_0ε_r)/(2pir) pir^2 (dF)/(dt)`

⇒ B = `(mu_0ε_r)/2 (dE)/(dt)`  .....`[because phi_E = Epir^2]`

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अध्याय 8: Electromagnetic Waves - MCQ I [पृष्ठ ५१]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 12
अध्याय 8 Electromagnetic Waves
MCQ I | Q 8.21 | पृष्ठ ५१

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संबंधित प्रश्न

Figure shows a capacitor made of two circular plates each of radius 12 cm, and separated by 5.0 cm. The capacitor is being charged by an external source (not shown in the figure). The charging current is constant and equal to 0.15 A.

  1. Calculate the capacitance and the rate of charge of the potential difference between the plates.
  2. Obtain the displacement current across the plates.
  3. Is Kirchhoff’s first rule (junction rule) valid at each plate of the capacitor? Explain.


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  1. What is the rms value of the conduction current?
  2. Is the conduction current equal to the displacement current?
  3. Determine the amplitude of B at a point 3.0 cm from the axis between the plates.


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