Advertisements
Advertisements
प्रश्न
Show that the magnetic field at a point due to a magnetic dipole is perpendicular to the magnetic axis if the line joining the point with the centre of the dipole makes an angle of `tan^-1(sqrt 2)` with the magnetic axis
Advertisements
उत्तर
Given :
Angle made by observation point P with the axis of the dipole, `θ = tan^-1 (sqrt 2)`
⇒ `tan θ = sqrt 2`
⇒ `2 = tan^2 θ`
⇒ `tan θ = cot θ`
⇒ `tan θ /2 = cot θ` .....(1)
we know ,
`tan θ /2 = tan α` ....(2)

On comparing (1) and (2), we get
`tan α = cot θ`
⇒ `tan α = tan (90 - θ)`
⇒ `α = 90 - θ`
⇒ `θ + α = 90^circ`
Hence, the magnetic field due to the dipole is perpendicular to the magnetic axis.
APPEARS IN
संबंधित प्रश्न
Why should the material used for making permanent magnets have high coercivity?
Can we have a single north pole, or a single south pole?
Which of the following four graphs may best represent the current-deflection relation in a tangent galvanometer?

A tangent galvanometer is connected directly to an ideal battery. If the number of turns in the coil is doubled the deflection will
Figure shows some of the equipotential surfaces of the magnetic scalar potential. Find the magnetic field B at a point in the region.

The magnetic field at a point, 10 cm away from a magnetic dipole, is found to be `2.0 xx 10^-4 "T"` . Find the magnetic moment of the dipole if the point is (a) in end-on position of the dipole and (b) in broadside-on position of the dipole.
Why is it not possible to make permanent magnets from paramagnetic materials?
The desirable properties for making permanent magnets are _________________ .
The coercive force for a certain permanent magnet is 4.0 × 104 A m−1. This magnet is placed inside a long solenoid of 40 turns/cm and a current is passed in the solenoid to demagnetise it completely. Find the current.
The magnetic field due to the earth has a horizontal component of 26 μT at a place where the dip is 60°. Find the vertical component and the magnitude of the field.
The needle of a dip circle shows an apparent dip of 45° in a particular position and 53° when the circle is rotated through 90°. Find the true dip.
Answer in brief.
Explain one application of electromagnet.
A thin diamagnetic rod is placed vertically between the poles of an electromagnet. When the current in the electromagnet is switched on, then the diamagnetic rod is pushed up, out of the horizontal magnetic field. Hence the rod gains gravitational potential energy. The work required to do this comes from ______.
A wire of length 2 m carrier of lamp is bend to form a circle. The magnetic moment of a coil is :-
A steel wire of length 1 has a magnetic moment m it is then bent into a semicircular arc. The new magnetic moment is
Which of the following is most suitable for the core of an electromagnet?
