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Prove that number of subsets of a set containing n distinct elements is 2n, for all n ∈ N. - Mathematics

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प्रश्न

Prove that number of subsets of a set containing n distinct elements is 2n, for all n ∈ N.

प्रमेय
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उत्तर

Let P(n) : Number of subsets of a set containing n distinct elements is 2n, ∀ n ∈ N

Step 1: It is clear that P(1) is true for n = 1.

Number of subsets = 21 = 2.

Which is true.

Step 2: P(k) is assumed to be true for n = k.

Since the number of subsets = 2k.

Step 3: P(k + 1) = 2k + 1

We know that if one number (i.e., element) is added to the elements of a given set, the number of subsets become double.

∴ Number of subsets of set having (k + 1) distinct elements = 2 × 2k = 2k + 1

Which is true for P(k + 1).

Hence P(k + 1) is true whenever P(k) is true.

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अध्याय 4: Principle of Mathematical Induction - Exercise [पृष्ठ ७२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 4 Principle of Mathematical Induction
Exercise | Q 25 | पृष्ठ ७२

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