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A sequence b0, b1, b2 ... is defined by letting b0 = 5 and bk = 4 + bk – 1 for all natural numbers k. Show that bn = 5 + 4n for all natural number n using mathematical induction. - Mathematics

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प्रश्न

A sequence b0, b1, b2 ... is defined by letting b0 = 5 and bk = 4 + bk – 1 for all natural numbers k. Show that bn = 5 + 4n for all natural number n using mathematical induction.

प्रमेय
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उत्तर

We have b0 = 5 and bk = 4 + bk – 1

⇒ b0 = 5, b1 = 4 + b0 = 4 + 5 = 9

And b2 = 4 + b1 = 4 + 9 = 13

Let P(n) : bn = 5 + 4n

Step 1: P(1) : b1 = 5 + 4 = 9 

⇒ 9 = 9 which is true.

Step 2: P(k): bk = 5 + 4k

Let it be true ∀ k ∈ N.

Step 3: Given that P(k) = 4 + bk – 1

⇒ P(k + 1) = 4 + bk+1–1

⇒ P(k + 1) = 4 + bk = 4 + 5 + 4k

⇒ P(k + 1) = 5 + 4(k + 1) which is true for P(k + 1).

Hence, P(k + 1) is true whenever P(k) is true.

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अध्याय 4: Principle of Mathematical Induction - Exercise [पृष्ठ ७१]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
अध्याय 4 Principle of Mathematical Induction
Exercise | Q 18 | पृष्ठ ७१

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