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प्रश्न
Predict all the alkenes that would be formed by dehydrohalogenation of the following halide with sodium ethoxide in ethanol and identify the major alkene:
2-Chloro-2-methylbutane
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उत्तर
2-Chloro-2-methylbutane has two different sets of equivalent β-hydrogens so that it will give 2 alkenes.
\[\begin{array}{cc}
\ce{\overset{β}{C}H3}\phantom{.................................}\ce{CH3}\phantom{..................}\ce{CH3}\phantom{..}\\
\phantom{}|\phantom{....................................}|\phantom{......................}|\phantom{....}\\
\ce{\overset{β}{C}H3 - C - \overset{β}{C}H2CH3 ->[C2H5ONa/C2H5OH][-HCl] \underset{2-Methylbut-1-ene}{CH2 = C - CH2CH3} + \underset{2-Methylbut-2-ene}{CH3 - C = CHCH3}}\\
|\phantom{...............................................................}\\
\ce{\underset{2-Chloro-2-methylbutane}{Cl}}\phantom{..............................................................}
\end{array}\]
Since the more substituted alkene will be more stable, 2-methylbut-2-ene will be the major alkene.
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संबंधित प्रश्न
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(I)
\[\ce{\underset{\text{(II)}}{CH3 - CH2 - Br}}\]
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\[\ce{CH3 C(CI) (C2H5)CH2CH3 }\]
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