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Integrate the rational function: x(x2+1)(x-1)

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प्रश्न

Integrate the rational function:

`x/((x^2+1)(x - 1))`

योग
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उत्तर

Let `x/((x^2 + 1)(x - 1)) = (Ax + B)/(x^2 + 1) + C/((x - 1))`

⇒ x = (A) (+ B)(x - 1) + C = `1/2`

Put x = 1

1 = 0 + 2C

⇒ C `= 1/2`

On comparing the coefficients of x2 or x

0 = A + C

⇒ A = `- 1/2`

and 1 = - A + B

⇒ B `= 1/2`

Hence, `int x/((x^2 + 1)(x - 1))  dx`

`= int (- 1/2  x + 1/2)/(x^2 + 1)  dx + 1/2 int 1/(x - 1)  dx`

`= -1/2 int (x - 1)/(x^2 + 1)  dx + 1/2  log abs (x - 1) + C`

`= 1/4 int (2x)/(x^2 + 1) + 1/2 int 1/(x^2 + 1)  dx + 1/2 log abs (x - 1) + C`

`= - 1/4  log abs (x^2 + 1) + 1/2  tan^-1 x + 1/2  log abs (x - 1) + C`

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अध्याय 7: Integrals - Exercise 7.5 [पृष्ठ ३२२]

APPEARS IN

एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 7 Integrals
Exercise 7.5 | Q 7 | पृष्ठ ३२२

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