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प्रश्न
Illustrate-combination of cells e.g., three cells, in parallel, explaining the combination briefly. Obtain an expression for current ‘i’ in the combination.
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उत्तर
Combination of cells in parallel: Let there be n cells, each of e.m.f. E and internal resistance r, be connected in parallel as shown in the diagram.
Total e.m.f. across the point A and B is E

Total internal resistance
`1/"r"_1 = 1/"r" + 1/"r" + 1/"r".... = "n"/"r"` (if there are n cells)
or r1 = `"r"/"n"`
But total resistance of circuit = R + `"r"/"n" = ("nR" + "r")/"n"`
∴ Current i = `"Total e.m.f"/"Total resistance"`
`= "E"/("R" + "r"/"n")`
`= "nE"/("nR + "r"")`
It is advantageous to join cells in parallel when the internal resistance of each cell is quite high as compared to the external resistance R.
Then, Approximately, i = `"nE"/"r"` (neglecting R).
संबंधित प्रश्न
An electrical appliance has a resistance of 25 Ω. When this electrical appliance is connected to a 230 V supply line, the current passing through it will be:
(a) 0.92 A
(b) 2.9 A
(c) 9.2 A
(d) 92 A
If the length of a wire is doubled by taking more of wire, what happens to its resistance?
How does the resistance of a wire change when:
its length is tripled?
When do you say that the resistors are connected in this way? Draw a circuit diagram.
State expression for Cells connected in parallel.
State and explain the laws of resistance.
Calculate the equivalent resistance between P and Q from the following diagram:
Two wires of same material and same lengths have radii in the ratio of 2 : 3, Compare their resistances.
If R1 and R2 be the resistance of the filament of 40 W and 60 W respectively operating 220 V, then:
