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Function F(X) = | X | − | X − 1 | is Monotonically Increasing When - Mathematics

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प्रश्न

Function f(x) = | x | − | x − 1 | is monotonically increasing when

 

 

 

 

 

 

 

 

 

 

 

विकल्प

  • x < 0

  •  x > 1

  • x < 1

  • 0 < x < 1

MCQ
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उत्तर

 0 < x < 1

\[f\left( x \right) = \left| x \right| - \left| x - 1 \right|\]

\[\text { Case 1: Let }x < 0 \]

\[\text { If x < 0 , then }\left| x \right| = - x\]

\[ \Rightarrow \left| x - 1 \right| = - \left( x - 1 \right)\]

\[\text { Now,}\]

\[f\left( x \right) = \left| x \right| - \left| x - 1 \right|\]

\[ = - x - \left( - x + 1 \right)\]

\[ = - x + x - 1\]

\[ = - 1\]

\[f'\left( x \right) = 0\]

\[\text { So,f }\left( x \right) \text { is not monotonically increasing when x< 0.}\]

\[\text { Case 2: Let }0 < x < 1\]

\[\text { Here,} \]

\[\left| x \right| = x\]

\[ \Rightarrow \left| x - 1 \right| = - \left( x - 1 \right)\]

\[\text { Now,}\]

\[f\left( x \right) = \left| x \right| - \left| x - 1 \right|\]

\[ = x + x - 1\]

\[ = 2x - 1\]

\[f'\left( x \right) = 2 > 0\]

\[\text { So },f\left( x \right) \text { is monotonically increasing when }0 < x < 1 . \]

\[\text { Case 3: Let x > 1} \]

\[\text { Ifx > 0, then }\left| x \right| = x\]

\[ \Rightarrow \left| x - 1 \right| = \left( x - 1 \right)\]

\[\text { Now,}\]

\[f\left( x \right) = \left| x \right| - \left| x - 1 \right|\]

\[ = x - x + 1\]

\[ = 1\]

\[f'\left( x \right) = 0\]

\[\text { So },f\left( x \right)\text {  is not monotonically  increasing when x >1 }.\]

\[\text { Thus },f\left( x \right) \text { is monotonically increasing when 0 < x < 1} . \]

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अध्याय 17: Increasing and Decreasing Functions - Exercise 17.4 [पृष्ठ ४१]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 17 Increasing and Decreasing Functions
Exercise 17.4 | Q 18 | पृष्ठ ४१

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