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प्रश्न
From the sum of 3a – 2b + 4c and 3b – 2c subtract a – b – c.
योग
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उत्तर
(3a – 2b + 4c) + (3b – 2c) – (a – b – c)
= 3a – 2b + 4c + 3b – 2c – a + b + c
= 3a – a + 3b + b – 2b + 4c + c – 2c
= 2a + 2b + 3c
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