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प्रश्न
Subtract x – 2y – z from the sum of 3x – y + z and x + y – 3z.
योग
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उत्तर
(3x – y + z) + (x + y – 3z) – (x – 2y – z)
= 3x – y + z + x + y – 3z – x + 2y + z
= 3x + x – x – y + y + 2y + z + z – 3z
= 3x + 2y – z
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